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131213424221039 is a prime number
BaseRepresentation
bin11101110101011010000001…
…100010100101101101101111
3122012120212210010202111002002
4131311122001202211231233
5114144300043100033124
61143022340454122515
736431566654333256
oct3565320142455557
9565525703674062
10131213424221039
1138899334278276
121287205a35043b
13582a4b00b3944
142458a9951d79d
151028267a810ae
hex7756818a5b6f

131213424221039 has 2 divisors, whose sum is σ = 131213424221040. Its totient is φ = 131213424221038.

The previous prime is 131213424220981. The next prime is 131213424221041. The reversal of 131213424221039 is 930122424312131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131213424221039 - 216 = 131213424155503 is a prime.

Together with 131213424221041, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 131213424220993 and 131213424221011.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131213424221839) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606712110519 + 65606712110520.

It is an arithmetic number, because the mean of its divisors is an integer number (65606712110520).

Almost surely, 2131213424221039 is an apocalyptic number.

131213424221039 is a deficient number, since it is larger than the sum of its proper divisors (1).

131213424221039 is an equidigital number, since it uses as much as digits as its factorization.

131213424221039 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 62208, while the sum is 38.

The spelling of 131213424221039 in words is "one hundred thirty-one trillion, two hundred thirteen billion, four hundred twenty-four million, two hundred twenty-one thousand, thirty-nine".