Base | Representation |
---|---|
bin | 10011000110000101001… |
… | …110001001000110101111 |
3 | 11122110000110222212100121 |
4 | 103012011032021012233 |
5 | 132444341211233234 |
6 | 2442452202105411 |
7 | 163542353556661 |
oct | 23060516110657 |
9 | 4573013885317 |
10 | 1312200102319 |
11 | 466556826687 |
12 | 1923911ab267 |
13 | 969808509b2 |
14 | 477219b4531 |
15 | 242000204b4 |
hex | 131853891af |
1312200102319 has 2 divisors, whose sum is σ = 1312200102320. Its totient is φ = 1312200102318.
The previous prime is 1312200102313. The next prime is 1312200102371. The reversal of 1312200102319 is 9132010022131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1312200102319 is a prime.
It is a super-2 number, since 2×13122001023192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1312200102293 and 1312200102302.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312200102313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656100051159 + 656100051160.
It is an arithmetic number, because the mean of its divisors is an integer number (656100051160).
Almost surely, 21312200102319 is an apocalyptic number.
1312200102319 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312200102319 is an equidigital number, since it uses as much as digits as its factorization.
1312200102319 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 1312200102319 in words is "one trillion, three hundred twelve billion, two hundred million, one hundred two thousand, three hundred nineteen".
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