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131220033119957 is a prime number
BaseRepresentation
bin11101110101100000001011…
…011101100010011011010101
3122012121111211201120100001002
4131311200023131202123111
5114144402111434314312
61143025352341513045
736432222514133165
oct3565401335423325
9565544751510032
10131220033119957
11388a1115884901
12128733a3712785
13582acc4372912
1424591251505a5
151028502d934c2
hex77580b7626d5

131220033119957 has 2 divisors, whose sum is σ = 131220033119958. Its totient is φ = 131220033119956.

The previous prime is 131220033119911. The next prime is 131220033120041. The reversal of 131220033119957 is 759911330022131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 125040836451556 + 6179196668401 = 11182166^2 + 2485799^2 .

It is a cyclic number.

It is not a de Polignac number, because 131220033119957 - 224 = 131220016342741 is a prime.

It is a super-2 number, since 2×1312200331199572 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131220033119657) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65610016559978 + 65610016559979.

It is an arithmetic number, because the mean of its divisors is an integer number (65610016559979).

Almost surely, 2131220033119957 is an apocalyptic number.

It is an amenable number.

131220033119957 is a deficient number, since it is larger than the sum of its proper divisors (1).

131220033119957 is an equidigital number, since it uses as much as digits as its factorization.

131220033119957 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 306180, while the sum is 47.

The spelling of 131220033119957 in words is "one hundred thirty-one trillion, two hundred twenty billion, thirty-three million, one hundred nineteen thousand, nine hundred fifty-seven".