Base | Representation |
---|---|
bin | 10011000110000101010… |
… | …101011011001000001011 |
3 | 11122110000121120211202221 |
4 | 103012011111123020023 |
5 | 132444342203324042 |
6 | 2442452311034511 |
7 | 163542406030036 |
oct | 23060525331013 |
9 | 4573017524687 |
10 | 1312202011147 |
11 | 46655790a825 |
12 | 19239196ba37 |
13 | 9698106b791 |
14 | 47721d5001d |
15 | 2420029ad67 |
hex | 1318555b20b |
1312202011147 has 2 divisors, whose sum is σ = 1312202011148. Its totient is φ = 1312202011146.
The previous prime is 1312202011129. The next prime is 1312202011229. The reversal of 1312202011147 is 7411102022131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1312202011147 - 235 = 1277842272779 is a prime.
It is not a weakly prime, because it can be changed into another prime (1316202011147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656101005573 + 656101005574.
It is an arithmetic number, because the mean of its divisors is an integer number (656101005574).
Almost surely, 21312202011147 is an apocalyptic number.
1312202011147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312202011147 is an equidigital number, since it uses as much as digits as its factorization.
1312202011147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 672, while the sum is 25.
Adding to 1312202011147 its reverse (7411102022131), we get a palindrome (8723304033278).
The spelling of 1312202011147 in words is "one trillion, three hundred twelve billion, two hundred two million, eleven thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.108 sec. • engine limits •