Base | Representation |
---|---|
bin | 1011111011110011011000… |
… | …0000111110000001101000 |
3 | 1201110110020220221112100202 |
4 | 2332330312000332001220 |
5 | 3204442410004004000 |
6 | 43524102235051332 |
7 | 2523015111553211 |
oct | 276746600760150 |
9 | 51413226845322 |
10 | 13122031313000 |
11 | 41aa027649395 |
12 | 157b1798a0b48 |
13 | 74252c96162c |
14 | 335177058408 |
15 | 17b502b37dd5 |
hex | bef3603e068 |
13122031313000 has 128 divisors (see below), whose sum is σ = 32326572096000. Its totient is φ = 4971799699200.
The previous prime is 13122031312927. The next prime is 13122031313071. The reversal of 13122031313000 is 31313022131.
13122031313000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 133197761 + ... + 133296239.
It is an arithmetic number, because the mean of its divisors is an integer number (252551344500).
Almost surely, 213122031313000 is an apocalyptic number.
13122031313000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13122031313000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16163286048000).
13122031313000 is an abundant number, since it is smaller than the sum of its proper divisors (19204540783000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13122031313000 is a wasteful number, since it uses less digits than its factorization.
13122031313000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 105532 (or 105518 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 13122031313000 its reverse (31313022131), we get a palindrome (13153344335131).
The spelling of 13122031313000 in words is "thirteen trillion, one hundred twenty-two billion, thirty-one million, three hundred thirteen thousand".
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