Base | Representation |
---|---|
bin | 1011111011110011011000… |
… | …1000100101111001001110 |
3 | 1201110110021001201001112020 |
4 | 2332330312020211321032 |
5 | 3204442411011430220 |
6 | 43524102345551010 |
7 | 2523015134545200 |
oct | 276746610457116 |
9 | 51413231631466 |
10 | 13122033311310 |
11 | 41aa028793790 |
12 | 157b17a4a5466 |
13 | 7425301b1071 |
14 | 335177418770 |
15 | 17b502dd0040 |
hex | bef36225e4e |
13122033311310 has 192 divisors, whose sum is σ = 42315873189120. Its totient is φ = 2566264673280.
The previous prime is 13122033311197. The next prime is 13122033311329. The reversal of 13122033311310 is 1311333022131.
It is a super-2 number, since 2×131220333113102 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 23592900 + ... + 24142679.
It is an arithmetic number, because the mean of its divisors is an integer number (220395172860).
Almost surely, 213122033311310 is an apocalyptic number.
13122033311310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13122033311310 is an abundant number, since it is smaller than the sum of its proper divisors (29193839877810).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13122033311310 is a wasteful number, since it uses less digits than its factorization.
13122033311310 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 47735631 (or 47735624 counting only the distinct ones).
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 13122033311310 its reverse (1311333022131), we get a palindrome (14433366333441).
The spelling of 13122033311310 in words is "thirteen trillion, one hundred twenty-two billion, thirty-three million, three hundred eleven thousand, three hundred ten".
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