Base | Representation |
---|---|
bin | 1011111011110011101000… |
… | …0111110010110111100101 |
3 | 1201110110102201120220212221 |
4 | 2332330322013302313211 |
5 | 3204443030123224143 |
6 | 43524113135512341 |
7 | 2523016606310422 |
oct | 276747207626745 |
9 | 51413381526787 |
10 | 13122100211173 |
11 | 41aa062527628 |
12 | 157b1989886b1 |
13 | 742541005795 |
14 | 335182270d49 |
15 | 17b508be72ed |
hex | bef3a1f2de5 |
13122100211173 has 2 divisors, whose sum is σ = 13122100211174. Its totient is φ = 13122100211172.
The previous prime is 13122100211167. The next prime is 13122100211369. The reversal of 13122100211173 is 37111200122131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9509964295329 + 3612135915844 = 3083823^2 + 1900562^2 .
It is a cyclic number.
It is not a de Polignac number, because 13122100211173 - 241 = 10923076955621 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13122100211873) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561050105586 + 6561050105587.
It is an arithmetic number, because the mean of its divisors is an integer number (6561050105587).
Almost surely, 213122100211173 is an apocalyptic number.
It is an amenable number.
13122100211173 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122100211173 is an equidigital number, since it uses as much as digits as its factorization.
13122100211173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 25.
The spelling of 13122100211173 in words is "thirteen trillion, one hundred twenty-two billion, one hundred million, two hundred eleven thousand, one hundred seventy-three".
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