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131221212181 is a prime number
BaseRepresentation
bin111101000110101100…
…1001100110000010101
3110112201000212020210121
41322031121030300111
54122220112242211
6140140541551541
712323532620503
oct1721531146025
9415630766717
10131221212181
1150717a539a4
12215218755b1
13c4b2bb50a7
1464cb75b673
15363018e271
hex1e8d64cc15

131221212181 has 2 divisors, whose sum is σ = 131221212182. Its totient is φ = 131221212180.

The previous prime is 131221212169. The next prime is 131221212203. The reversal of 131221212181 is 181212122131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 107862980625 + 23358231556 = 328425^2 + 152834^2 .

It is an emirp because it is prime and its reverse (181212122131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131221212181 - 25 = 131221212149 is a prime.

It is a super-2 number, since 2×1312212121812 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131221212121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65610606090 + 65610606091.

It is an arithmetic number, because the mean of its divisors is an integer number (65610606091).

Almost surely, 2131221212181 is an apocalyptic number.

It is an amenable number.

131221212181 is a deficient number, since it is larger than the sum of its proper divisors (1).

131221212181 is an equidigital number, since it uses as much as digits as its factorization.

131221212181 is an evil number, because the sum of its binary digits is even.

The product of its digits is 384, while the sum is 25.

The spelling of 131221212181 in words is "one hundred thirty-one billion, two hundred twenty-one million, two hundred twelve thousand, one hundred eighty-one".