Base | Representation |
---|---|
bin | 10011000110000110011… |
… | …010110110110010001111 |
3 | 11122110001212211120011012 |
4 | 103012012122312302033 |
5 | 132444411333243432 |
6 | 2442454201115435 |
7 | 163543016524601 |
oct | 23060632666217 |
9 | 4573055746135 |
10 | 1312220212367 |
11 | 466567111659 |
12 | 192397a88b7b |
13 | 96984a7222c |
14 | 4772452b171 |
15 | 24201b93cb2 |
hex | 131866b6c8f |
1312220212367 has 2 divisors, whose sum is σ = 1312220212368. Its totient is φ = 1312220212366.
The previous prime is 1312220212361. The next prime is 1312220212411. The reversal of 1312220212367 is 7632120222131.
It is a weak prime.
It is an emirp because it is prime and its reverse (7632120222131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1312220212367 - 24 = 1312220212351 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312220212361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656110106183 + 656110106184.
It is an arithmetic number, because the mean of its divisors is an integer number (656110106184).
Almost surely, 21312220212367 is an apocalyptic number.
1312220212367 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312220212367 is an equidigital number, since it uses as much as digits as its factorization.
1312220212367 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 32.
Adding to 1312220212367 its reverse (7632120222131), we get a palindrome (8944340434498).
The spelling of 1312220212367 in words is "one trillion, three hundred twelve billion, two hundred twenty million, two hundred twelve thousand, three hundred sixty-seven".
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