131222130101 has 2 divisors, whose sum is σ = 131222130102. Its totient is φ = 131222130100.

The previous prime is 131222130071. The next prime is 131222130103. The reversal of 131222130101 is 101031222131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72575821201 + 58646308900 = 269399^2 + 242170^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131222130101 is a prime.

Together with 131222130103, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131222130101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131222130103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65611065050 + 65611065051.

It is an arithmetic number, because the mean of its divisors is an integer number (65611065051).

Almost surely, 2^131222130101 is an apocalyptic number.

It is an amenable number.

131222130101 is a deficient number, since it is larger than the sum of its proper divisors (1).

131222130101 is an equidigital number, since it uses as much as digits as its factorization.

131222130101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 131222130101 its reverse (101031222131), we get a palindrome (232253352232).

The spelling of 131222130101 in words is "one hundred thirty-one billion, two hundred twenty-two million, one hundred thirty thousand, one hundred one".