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13122232000301 is a prime number
BaseRepresentation
bin1011111011110100000111…
…1110100001111100101101
31201110110202220120111120202
42332331001332201330231
53204443312343002201
643524134204323245
72523023066432324
oct276750176417455
951413686514522
1013122232000301
1141aa11a960766
12157b214b43525
137425623c9708
143351959790bb
1517b51557ac6b
hexbef41fa1f2d

13122232000301 has 2 divisors, whose sum is σ = 13122232000302. Its totient is φ = 13122232000300.

The previous prime is 13122232000243. The next prime is 13122232000303. The reversal of 13122232000301 is 10300023222131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10093970764201 + 3028261236100 = 3177101^2 + 1740190^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13122232000301 is a prime.

It is a Sophie Germain prime.

Together with 13122232000303, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13122232000303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561116000150 + 6561116000151.

It is an arithmetic number, because the mean of its divisors is an integer number (6561116000151).

Almost surely, 213122232000301 is an apocalyptic number.

It is an amenable number.

13122232000301 is a deficient number, since it is larger than the sum of its proper divisors (1).

13122232000301 is an equidigital number, since it uses as much as digits as its factorization.

13122232000301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 13122232000301 its reverse (10300023222131), we get a palindrome (23422255222432).

The spelling of 13122232000301 in words is "thirteen trillion, one hundred twenty-two billion, two hundred thirty-two million, three hundred one", and thus it is an aban number.