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131222332422943 is a prime number
BaseRepresentation
bin11101110101100010010100…
…100000101011101100011111
3122012121201202222010000202221
4131311202110200223230133
5114144421314100013233
61143030412435530211
736432333503652346
oct3565422440535437
9565551688100687
10131222332422943
11388a209576a203
1212873925759967
13582b29c832728
1424592a267ab5d
1510285d9b7842d
hex77589482bb1f

131222332422943 has 2 divisors, whose sum is σ = 131222332422944. Its totient is φ = 131222332422942.

The previous prime is 131222332422917. The next prime is 131222332423027. The reversal of 131222332422943 is 349224233222131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131222332422943 is a prime.

It is a super-3 number, since 3×1312223324229433 (a number of 43 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131222332422943.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131222332422913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65611166211471 + 65611166211472.

It is an arithmetic number, because the mean of its divisors is an integer number (65611166211472).

Almost surely, 2131222332422943 is an apocalyptic number.

131222332422943 is a deficient number, since it is larger than the sum of its proper divisors (1).

131222332422943 is an equidigital number, since it uses as much as digits as its factorization.

131222332422943 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 746496, while the sum is 43.

The spelling of 131222332422943 in words is "one hundred thirty-one trillion, two hundred twenty-two billion, three hundred thirty-two million, four hundred twenty-two thousand, nine hundred forty-three".