Base | Representation |
---|---|
bin | 11101110101100010010100… |
… | …100000101011101101110011 |
3 | 122012121201202222010000220001 |
4 | 131311202110200223231303 |
5 | 114144421314100014102 |
6 | 1143030412435530431 |
7 | 36432333503652526 |
oct | 3565422440535563 |
9 | 565551688100801 |
10 | 131222332423027 |
11 | 388a209576a27a |
12 | 12873925759a17 |
13 | 582b29c832791 |
14 | 24592a267abbd |
15 | 10285d9b78487 |
hex | 77589482bb73 |
131222332423027 has 2 divisors, whose sum is σ = 131222332423028. Its totient is φ = 131222332423026.
The previous prime is 131222332422943. The next prime is 131222332423037. The reversal of 131222332423027 is 720324233222131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131222332423027 - 211 = 131222332420979 is a prime.
It is a super-3 number, since 3×1312223324230273 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (131222332423037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65611166211513 + 65611166211514.
It is an arithmetic number, because the mean of its divisors is an integer number (65611166211514).
Almost surely, 2131222332423027 is an apocalyptic number.
131222332423027 is a deficient number, since it is larger than the sum of its proper divisors (1).
131222332423027 is an equidigital number, since it uses as much as digits as its factorization.
131222332423027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 145152, while the sum is 37.
Adding to 131222332423027 its reverse (720324233222131), we get a palindrome (851546565645158).
The spelling of 131222332423027 in words is "one hundred thirty-one trillion, two hundred twenty-two billion, three hundred thirty-two million, four hundred twenty-three thousand, twenty-seven".
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