Base | Representation |
---|---|
bin | 1011111011110100011000… |
… | …0011101010011011011011 |
3 | 1201110110221200101100020212 |
4 | 2332331012003222123123 |
5 | 3204443432404021434 |
6 | 43524145051441335 |
7 | 2523024560330516 |
oct | 276750603523333 |
9 | 51413850340225 |
10 | 13122300454619 |
11 | 41aa155566484 |
12 | 157b233a5624b |
13 | 742573646825 |
14 | 3351a0ab7d7d |
15 | 17b51b59d8ce |
hex | bef460ea6db |
13122300454619 has 2 divisors, whose sum is σ = 13122300454620. Its totient is φ = 13122300454618.
The previous prime is 13122300454537. The next prime is 13122300454621. The reversal of 13122300454619 is 91645400322131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13122300454619 is a prime.
It is a super-2 number, since 2×131223004546192 (a number of 27 digits) contains 22 as substring.
Together with 13122300454621, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13122300454649) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561150227309 + 6561150227310.
It is an arithmetic number, because the mean of its divisors is an integer number (6561150227310).
Almost surely, 213122300454619 is an apocalyptic number.
13122300454619 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122300454619 is an equidigital number, since it uses as much as digits as its factorization.
13122300454619 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 41.
The spelling of 13122300454619 in words is "thirteen trillion, one hundred twenty-two billion, three hundred million, four hundred fifty-four thousand, six hundred nineteen".
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