Base | Representation |
---|---|
bin | 10011000110000111001… |
… | …000001101110001110110 |
3 | 11122110002201012200002010 |
4 | 103012013020031301312 |
5 | 132444422404244110 |
6 | 2442455304025050 |
7 | 163543222560342 |
oct | 23060710156166 |
9 | 4573081180063 |
10 | 1312232103030 |
11 | 4665728a3252 |
12 | 19239ba62186 |
13 | 96987376524 |
14 | 47725d44622 |
15 | 24202c42020 |
hex | 1318720dc76 |
1312232103030 has 16 divisors (see below), whose sum is σ = 3149357047344. Its totient is φ = 349928560800.
The previous prime is 1312232102989. The next prime is 1312232103101. The reversal of 1312232103030 is 303012322131.
It is a junction number, because it is equal to n+sod(n) for n = 1312232102988 and 1312232103006.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21870535021 + ... + 21870535080.
It is an arithmetic number, because the mean of its divisors is an integer number (196834815459).
Almost surely, 21312232103030 is an apocalyptic number.
1312232103030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1312232103030 is an abundant number, since it is smaller than the sum of its proper divisors (1837124944314).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1312232103030 is a wasteful number, since it uses less digits than its factorization.
1312232103030 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 43741070111.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 1312232103030 its reverse (303012322131), we get a palindrome (1615244425161).
The spelling of 1312232103030 in words is "one trillion, three hundred twelve billion, two hundred thirty-two million, one hundred three thousand, thirty".
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