Base | Representation |
---|---|
bin | 10011000110000111100… |
… | …111111000001100100101 |
3 | 11122110010021211100211012 |
4 | 103012013213320030211 |
5 | 132444432020400422 |
6 | 2442500201552005 |
7 | 163543353250241 |
oct | 23060747701445 |
9 | 4573107740735 |
10 | 1312240403237 |
11 | 466577552325 |
12 | 1923a27a5605 |
13 | 96988cc14aa |
14 | 477270a5421 |
15 | 242038314e2 |
hex | 131879f8325 |
1312240403237 has 2 divisors, whose sum is σ = 1312240403238. Its totient is φ = 1312240403236.
The previous prime is 1312240403171. The next prime is 1312240403261. The reversal of 1312240403237 is 7323040422131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1137036209761 + 175204193476 = 1066319^2 + 418574^2 .
It is a cyclic number.
It is not a de Polignac number, because 1312240403237 - 220 = 1312239354661 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312240403297) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656120201618 + 656120201619.
It is an arithmetic number, because the mean of its divisors is an integer number (656120201619).
Almost surely, 21312240403237 is an apocalyptic number.
It is an amenable number.
1312240403237 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312240403237 is an equidigital number, since it uses as much as digits as its factorization.
1312240403237 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 32.
Adding to 1312240403237 its reverse (7323040422131), we get a palindrome (8635280825368).
The spelling of 1312240403237 in words is "one trillion, three hundred twelve billion, two hundred forty million, four hundred three thousand, two hundred thirty-seven".
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