Base | Representation |
---|---|
bin | 1011111011110100110011… |
… | …0001111000001101101000 |
3 | 1201110111020112121002002221 |
4 | 2332331030301320031220 |
5 | 3204444200241424000 |
6 | 43524204201003424 |
7 | 2523030430043461 |
oct | 276751461701550 |
9 | 51414215532087 |
10 | 13122413233000 |
11 | 41aa203195555 |
12 | 157b265783574 |
13 | 742590b126b6 |
14 | 3351b1a73d68 |
15 | 17b52642961a |
hex | bef4cc78368 |
13122413233000 has 64 divisors (see below), whose sum is σ = 30707167158720. Its totient is φ = 5248842184000.
The previous prime is 13122413232997. The next prime is 13122413233043. The reversal of 13122413233000 is 33231422131.
It is a super-2 number, since 2×131224132330002 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 51002679 + ... + 51259321.
It is an arithmetic number, because the mean of its divisors is an integer number (479799486855).
Almost surely, 213122413233000 is an apocalyptic number.
13122413233000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13122413233000 is an abundant number, since it is smaller than the sum of its proper divisors (17584753925720).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13122413233000 is a wasteful number, since it uses less digits than its factorization.
13122413233000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 307795 (or 307781 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 13122413233000 its reverse (33231422131), we get a palindrome (13155644655131).
The spelling of 13122413233000 in words is "thirteen trillion, one hundred twenty-two billion, four hundred thirteen million, two hundred thirty-three thousand".
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