Base | Representation |
---|---|
bin | 1011111011110100110011… |
… | …0010111101000110001111 |
3 | 1201110111020120010102010222 |
4 | 2332331030302331012033 |
5 | 3204444200324441101 |
6 | 43524204211021555 |
7 | 2523030432330203 |
oct | 276751462750617 |
9 | 51414216112128 |
10 | 13122413515151 |
11 | 41aa203368536 |
12 | 157b26589a8bb |
13 | 742590bb0c55 |
14 | 3351b1b08b03 |
15 | 17b52648301b |
hex | bef4ccbd18f |
13122413515151 has 2 divisors, whose sum is σ = 13122413515152. Its totient is φ = 13122413515150.
The previous prime is 13122413515129. The next prime is 13122413515231. The reversal of 13122413515151 is 15151531422131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13122413515151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13122413515111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561206757575 + 6561206757576.
It is an arithmetic number, because the mean of its divisors is an integer number (6561206757576).
Almost surely, 213122413515151 is an apocalyptic number.
13122413515151 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122413515151 is an equidigital number, since it uses as much as digits as its factorization.
13122413515151 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 18000, while the sum is 35.
Adding to 13122413515151 its reverse (15151531422131), we get a palindrome (28273944937282).
The spelling of 13122413515151 in words is "thirteen trillion, one hundred twenty-two billion, four hundred thirteen million, five hundred fifteen thousand, one hundred fifty-one".
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