Base | Representation |
---|---|
bin | 1011111011110100110011… |
… | …0100110011100101010011 |
3 | 1201110111020121001001212122 |
4 | 2332331030310303211103 |
5 | 3204444200441003332 |
6 | 43524204225244455 |
7 | 2523030436421132 |
oct | 276751464634523 |
9 | 51414217031778 |
10 | 13122414000467 |
11 | 41aa20366a122 |
12 | 157b265a9372b |
13 | 742591020b15 |
14 | 3351b1bd3919 |
15 | 17b52652bc12 |
hex | bef4cd33953 |
13122414000467 has 2 divisors, whose sum is σ = 13122414000468. Its totient is φ = 13122414000466.
The previous prime is 13122414000439. The next prime is 13122414000499. The reversal of 13122414000467 is 76400041422131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13122414000467 - 224 = 13122397223251 is a prime.
It is not a weakly prime, because it can be changed into another prime (13122414000067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561207000233 + 6561207000234.
It is an arithmetic number, because the mean of its divisors is an integer number (6561207000234).
Almost surely, 213122414000467 is an apocalyptic number.
13122414000467 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122414000467 is an equidigital number, since it uses as much as digits as its factorization.
13122414000467 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32256, while the sum is 35.
Adding to 13122414000467 its reverse (76400041422131), we get a palindrome (89522455422598).
The spelling of 13122414000467 in words is "thirteen trillion, one hundred twenty-two billion, four hundred fourteen million, four hundred sixty-seven", and thus it is an aban number.
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