Base | Representation |
---|---|
bin | 1011111011110100110011… |
… | …0100110011100100110111 |
3 | 1201110111020121001001211121 |
4 | 2332331030310303210313 |
5 | 3204444200441003224 |
6 | 43524204225244411 |
7 | 2523030436421062 |
oct | 276751464634467 |
9 | 51414217031747 |
10 | 13122414000439 |
11 | 41aa20366a0a7 |
12 | 157b265a93707 |
13 | 742591020ac3 |
14 | 3351b1bd38d9 |
15 | 17b52652bbe4 |
hex | bef4cd33937 |
13122414000439 has 2 divisors, whose sum is σ = 13122414000440. Its totient is φ = 13122414000438.
The previous prime is 13122414000433. The next prime is 13122414000467. The reversal of 13122414000439 is 93400041422131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13122414000439 - 23 = 13122414000431 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13122414000431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561207000219 + 6561207000220.
It is an arithmetic number, because the mean of its divisors is an integer number (6561207000220).
Almost surely, 213122414000439 is an apocalyptic number.
13122414000439 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122414000439 is an equidigital number, since it uses as much as digits as its factorization.
13122414000439 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20736, while the sum is 34.
The spelling of 13122414000439 in words is "thirteen trillion, one hundred twenty-two billion, four hundred fourteen million, four hundred thirty-nine", and thus it is an aban number.
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