Base | Representation |
---|---|
bin | 1011111011110100110011… |
… | …0100110011100101110011 |
3 | 1201110111020121001001220211 |
4 | 2332331030310303211303 |
5 | 3204444200441003444 |
6 | 43524204225244551 |
7 | 2523030436421206 |
oct | 276751464634563 |
9 | 51414217031824 |
10 | 13122414000499 |
11 | 41aa20366a151 |
12 | 157b265a93757 |
13 | 742591020b3b |
14 | 3351b1bd393d |
15 | 17b52652bc34 |
hex | bef4cd33973 |
13122414000499 has 2 divisors, whose sum is σ = 13122414000500. Its totient is φ = 13122414000498.
The previous prime is 13122414000467. The next prime is 13122414000511. The reversal of 13122414000499 is 99400041422131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13122414000499 - 25 = 13122414000467 is a prime.
It is not a weakly prime, because it can be changed into another prime (13122414000439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561207000249 + 6561207000250.
It is an arithmetic number, because the mean of its divisors is an integer number (6561207000250).
Almost surely, 213122414000499 is an apocalyptic number.
13122414000499 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122414000499 is an equidigital number, since it uses as much as digits as its factorization.
13122414000499 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 62208, while the sum is 40.
The spelling of 13122414000499 in words is "thirteen trillion, one hundred twenty-two billion, four hundred fourteen million, four hundred ninety-nine", and thus it is an aban number.
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