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13122414000499 is a prime number
BaseRepresentation
bin1011111011110100110011…
…0100110011100101110011
31201110111020121001001220211
42332331030310303211303
53204444200441003444
643524204225244551
72523030436421206
oct276751464634563
951414217031824
1013122414000499
1141aa20366a151
12157b265a93757
13742591020b3b
143351b1bd393d
1517b52652bc34
hexbef4cd33973

13122414000499 has 2 divisors, whose sum is σ = 13122414000500. Its totient is φ = 13122414000498.

The previous prime is 13122414000467. The next prime is 13122414000511. The reversal of 13122414000499 is 99400041422131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13122414000499 - 25 = 13122414000467 is a prime.

It is not a weakly prime, because it can be changed into another prime (13122414000439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561207000249 + 6561207000250.

It is an arithmetic number, because the mean of its divisors is an integer number (6561207000250).

Almost surely, 213122414000499 is an apocalyptic number.

13122414000499 is a deficient number, since it is larger than the sum of its proper divisors (1).

13122414000499 is an equidigital number, since it uses as much as digits as its factorization.

13122414000499 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 62208, while the sum is 40.

The spelling of 13122414000499 in words is "thirteen trillion, one hundred twenty-two billion, four hundred fourteen million, four hundred ninety-nine", and thus it is an aban number.