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13122433422013 is a prime number
BaseRepresentation
bin1011111011110100110111…
…1110111001001010111101
31201110111021221120210020011
42332331031332321022331
53204444220424001023
643524210201423221
72523031063460536
oct276751576711275
951414257523204
1013122433422013
1141aa213624893
12157b27049ab11
13742595060b66
143351b460b68d
1517b5280b650d
hexbef4dfb92bd

13122433422013 has 2 divisors, whose sum is σ = 13122433422014. Its totient is φ = 13122433422012.

The previous prime is 13122433421987. The next prime is 13122433422143. The reversal of 13122433422013 is 31022433422131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9458589532324 + 3663843889689 = 3075482^2 + 1914117^2 .

It is an emirp because it is prime and its reverse (31022433422131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13122433422013 - 213 = 13122433413821 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13122433422713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561216711006 + 6561216711007.

It is an arithmetic number, because the mean of its divisors is an integer number (6561216711007).

Almost surely, 213122433422013 is an apocalyptic number.

It is an amenable number.

13122433422013 is a deficient number, since it is larger than the sum of its proper divisors (1).

13122433422013 is an equidigital number, since it uses as much as digits as its factorization.

13122433422013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 13122433422013 its reverse (31022433422131), we get a palindrome (44144866844144).

The spelling of 13122433422013 in words is "thirteen trillion, one hundred twenty-two billion, four hundred thirty-three million, four hundred twenty-two thousand, thirteen".