Base | Representation |
---|---|
bin | 1011111011110100110111… |
… | …1110111001001100111111 |
3 | 1201110111021221120210101222 |
4 | 2332331031332321030333 |
5 | 3204444220424002033 |
6 | 43524210201423555 |
7 | 2523031063461113 |
oct | 276751576711477 |
9 | 51414257523358 |
10 | 13122433422143 |
11 | 41aa2136249a1 |
12 | 157b27049abbb |
13 | 742595060c36 |
14 | 3351b460b743 |
15 | 17b5280b6598 |
hex | bef4dfb933f |
13122433422143 has 2 divisors, whose sum is σ = 13122433422144. Its totient is φ = 13122433422142.
The previous prime is 13122433422013. The next prime is 13122433422187. The reversal of 13122433422143 is 34122433422131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13122433422143 - 218 = 13122433159999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13122433022143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561216711071 + 6561216711072.
It is an arithmetic number, because the mean of its divisors is an integer number (6561216711072).
Almost surely, 213122433422143 is an apocalyptic number.
13122433422143 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122433422143 is an equidigital number, since it uses as much as digits as its factorization.
13122433422143 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 82944, while the sum is 35.
Adding to 13122433422143 its reverse (34122433422131), we get a palindrome (47244866844274).
The spelling of 13122433422143 in words is "thirteen trillion, one hundred twenty-two billion, four hundred thirty-three million, four hundred twenty-two thousand, one hundred forty-three".
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