Base | Representation |
---|---|
bin | 1011111011110100111100… |
… | …0010110110001001011111 |
3 | 1201110111100012002210122002 |
4 | 2332331033002312021133 |
5 | 3204444240004013143 |
6 | 43524212035312515 |
7 | 2523031401051635 |
oct | 276751702661137 |
9 | 51414305083562 |
10 | 13122451235423 |
11 | 41aa222691312 |
12 | 157b27644b73b |
13 | 742598959c3a |
14 | 3351b6b27355 |
15 | 17b5299345b8 |
hex | bef4f0b625f |
13122451235423 has 2 divisors, whose sum is σ = 13122451235424. Its totient is φ = 13122451235422.
The previous prime is 13122451235381. The next prime is 13122451235429. The reversal of 13122451235423 is 32453215422131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13122451235423 - 218 = 13122450973279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13122451235429) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561225617711 + 6561225617712.
It is an arithmetic number, because the mean of its divisors is an integer number (6561225617712).
Almost surely, 213122451235423 is an apocalyptic number.
13122451235423 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122451235423 is an equidigital number, since it uses as much as digits as its factorization.
13122451235423 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 172800, while the sum is 38.
Adding to 13122451235423 its reverse (32453215422131), we get a palindrome (45575666657554).
The spelling of 13122451235423 in words is "thirteen trillion, one hundred twenty-two billion, four hundred fifty-one million, two hundred thirty-five thousand, four hundred twenty-three".
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