Base | Representation |
---|---|
bin | 1011111011110100111101… |
… | …0010001011000100111111 |
3 | 1201110111100110122221010202 |
4 | 2332331033102023010333 |
5 | 3204444242021101221 |
6 | 43524212301354115 |
7 | 2523031450154615 |
oct | 276751722130477 |
9 | 51414313587122 |
10 | 13122455253311 |
11 | 41aa224985a88 |
12 | 157b27786893b |
13 | 7425997359a1 |
14 | 3351b74916b5 |
15 | 17b529e79d0b |
hex | bef4f48b13f |
13122455253311 has 2 divisors, whose sum is σ = 13122455253312. Its totient is φ = 13122455253310.
The previous prime is 13122455253263. The next prime is 13122455253343. The reversal of 13122455253311 is 11335255422131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13122455253311 - 218 = 13122454991167 is a prime.
It is a super-2 number, since 2×131224552533112 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13122455253371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561227626655 + 6561227626656.
It is an arithmetic number, because the mean of its divisors is an integer number (6561227626656).
Almost surely, 213122455253311 is an apocalyptic number.
13122455253311 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122455253311 is an equidigital number, since it uses as much as digits as its factorization.
13122455253311 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 108000, while the sum is 38.
The spelling of 13122455253311 in words is "thirteen trillion, one hundred twenty-two billion, four hundred fifty-five million, two hundred fifty-three thousand, three hundred eleven".
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