Base | Representation |
---|---|
bin | 10011000110000111111… |
… | …110110110001010101001 |
3 | 11122110010201011021002001 |
4 | 103012013332312022221 |
5 | 132444440041033413 |
6 | 2442500535011001 |
7 | 163543455365203 |
oct | 23060776661251 |
9 | 4573121137061 |
10 | 1312246424233 |
11 | 46657a994a58 |
12 | 1923a4809a61 |
13 | 9698a31bc04 |
14 | 47727bd1773 |
15 | 242041204dd |
hex | 13187fb62a9 |
1312246424233 has 2 divisors, whose sum is σ = 1312246424234. Its totient is φ = 1312246424232.
The previous prime is 1312246424231. The next prime is 1312246424267. The reversal of 1312246424233 is 3324246422131.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 739663641369 + 572582782864 = 860037^2 + 756692^2 .
It is an emirp because it is prime and its reverse (3324246422131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1312246424233 - 21 = 1312246424231 is a prime.
Together with 1312246424231, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 1312246424192 and 1312246424201.
It is not a weakly prime, because it can be changed into another prime (1312246424231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656123212116 + 656123212117.
It is an arithmetic number, because the mean of its divisors is an integer number (656123212117).
Almost surely, 21312246424233 is an apocalyptic number.
It is an amenable number.
1312246424233 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312246424233 is an equidigital number, since it uses as much as digits as its factorization.
1312246424233 is an evil number, because the sum of its binary digits is even.
The product of its digits is 165888, while the sum is 37.
The spelling of 1312246424233 in words is "one trillion, three hundred twelve billion, two hundred forty-six million, four hundred twenty-four thousand, two hundred thirty-three".
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