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13123011119 is a prime number
BaseRepresentation
bin11000011100011000…
…10100001000101111
31020212120021000222212
430032030110020233
5203333442323434
610010103401035
7643125516431
oct141614241057
936776230885
1013123011119
115624663539
122662a5317b
131311a1134a
148c6c2a651
1551c14e8ce
hex30e31422f

13123011119 has 2 divisors, whose sum is σ = 13123011120. Its totient is φ = 13123011118.

The previous prime is 13123011113. The next prime is 13123011133. The reversal of 13123011119 is 91111032131.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13123011119 is a prime.

It is a super-2 number, since 2×131230111192 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13123011094 and 13123011103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13123011113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561505559 + 6561505560.

It is an arithmetic number, because the mean of its divisors is an integer number (6561505560).

Almost surely, 213123011119 is an apocalyptic number.

13123011119 is a deficient number, since it is larger than the sum of its proper divisors (1).

13123011119 is an equidigital number, since it uses as much as digits as its factorization.

13123011119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 23.

The spelling of 13123011119 in words is "thirteen billion, one hundred twenty-three million, eleven thousand, one hundred nineteen".