Base | Representation |
---|---|
bin | 11101110101101001110000… |
… | …000001001001101111100110 |
3 | 122012122111100221112122010112 |
4 | 131311221300001021233212 |
5 | 114200034133342042410 |
6 | 1143034212221253022 |
7 | 36433035264130610 |
oct | 3565516001115746 |
9 | 565574327478115 |
10 | 131230310112230 |
11 | 388a550998924a |
12 | 12875391404172 |
13 | 582bc71563734 |
14 | 245981bdb7db0 |
15 | 1028905218105 |
hex | 775a70049be6 |
131230310112230 has 64 divisors (see below), whose sum is σ = 276552127660032. Its totient is φ = 43894542600960.
The previous prime is 131230310112199. The next prime is 131230310112241. The reversal of 131230310112230 is 32211013032131.
It is a junction number, because it is equal to n+sod(n) for n = 131230310112196 and 131230310112205.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 97968047 + ... + 99298533.
It is an arithmetic number, because the mean of its divisors is an integer number (4321126994688).
Almost surely, 2131230310112230 is an apocalyptic number.
131230310112230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131230310112230 is an abundant number, since it is smaller than the sum of its proper divisors (145321817547802).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131230310112230 is a wasteful number, since it uses less digits than its factorization.
131230310112230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1364909.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 131230310112230 its reverse (32211013032131), we get a palindrome (163441323144361).
The spelling of 131230310112230 in words is "one hundred thirty-one trillion, two hundred thirty billion, three hundred ten million, one hundred twelve thousand, two hundred thirty".
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