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131230312995919 is a prime number
BaseRepresentation
bin11101110101101001110000…
…001100001001110001001111
3122012122111101010222010210211
4131311221300030021301033
5114200034140111332134
61143034212403143251
736433035330501064
oct3565516014116117
9565574333863724
10131230312995919
11388a5510578865
1212875392374b27
13582bc72033167
14245981c528c6b
1510289055d7764
hex775a70309c4f

131230312995919 has 2 divisors, whose sum is σ = 131230312995920. Its totient is φ = 131230312995918.

The previous prime is 131230312995907. The next prime is 131230312995931. The reversal of 131230312995919 is 919599213032131.

It is a balanced prime because it is at equal distance from previous prime (131230312995907) and next prime (131230312995931).

It is an emirp because it is prime and its reverse (919599213032131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131230312995919 - 221 = 131230310898767 is a prime.

It is a super-2 number, since 2×1312303129959192 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131230312990919) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65615156497959 + 65615156497960.

It is an arithmetic number, because the mean of its divisors is an integer number (65615156497960).

Almost surely, 2131230312995919 is an apocalyptic number.

131230312995919 is a deficient number, since it is larger than the sum of its proper divisors (1).

131230312995919 is an equidigital number, since it uses as much as digits as its factorization.

131230312995919 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3542940, while the sum is 58.

The spelling of 131230312995919 in words is "one hundred thirty-one trillion, two hundred thirty billion, three hundred twelve million, nine hundred ninety-five thousand, nine hundred nineteen".