Base | Representation |
---|---|
bin | 111101000110111111… |
… | …0100100110010001101 |
3 | 110112201201022000210022 |
4 | 1322031332210302031 |
5 | 4122230114304213 |
6 | 140141531551525 |
7 | 12324012115412 |
oct | 1721576446215 |
9 | 415651260708 |
10 | 131231009933 |
11 | 50722536111 |
12 | 21524bbb5a5 |
13 | c4b4c3588a |
14 | 64ccb8c109 |
15 | 3630e77308 |
hex | 1e8dfa4c8d |
131231009933 has 2 divisors, whose sum is σ = 131231009934. Its totient is φ = 131231009932.
The previous prime is 131231009929. The next prime is 131231009951. The reversal of 131231009933 is 339900132131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 94527347209 + 36703662724 = 307453^2 + 191582^2 .
It is a cyclic number.
It is not a de Polignac number, because 131231009933 - 22 = 131231009929 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131231009893 and 131231009902.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131231009983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65615504966 + 65615504967.
It is an arithmetic number, because the mean of its divisors is an integer number (65615504967).
Almost surely, 2131231009933 is an apocalyptic number.
It is an amenable number.
131231009933 is a deficient number, since it is larger than the sum of its proper divisors (1).
131231009933 is an equidigital number, since it uses as much as digits as its factorization.
131231009933 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13122, while the sum is 35.
The spelling of 131231009933 in words is "one hundred thirty-one billion, two hundred thirty-one million, nine thousand, nine hundred thirty-three".
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