13123111013130 has 32 divisors (see below), whose sum is σ = 31504467960000. Its totient is φ = 3498496100352.

The previous prime is 13123111013021. The next prime is 13123111013143. The reversal of 13123111013130 is 3131011132131.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13123111013097 and 13123111013106.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 62403895 + ... + 62613834.

It is an arithmetic number, because the mean of its divisors is an integer number (984514623750).

Almost surely, 2^{13123111013130} is an apocalyptic number.

13123111013130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13123111013130 is an abundant number, since it is smaller than the sum of its proper divisors (18381356946870).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13123111013130 is a wasteful number, since it uses less digits than its factorization.

13123111013130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 125021238.

The product of its (nonzero) digits is 162, while the sum is 21.

Adding to 13123111013130 its reverse (3131011132131), we get a palindrome (16254122145261).

The spelling of 13123111013130 in words is "thirteen trillion, one hundred twenty-three billion, one hundred eleven million, thirteen thousand, one hundred thirty".