Base | Representation |
---|---|
bin | 11101110101101010110000… |
… | …111111010010001000011111 |
3 | 122012122121011220121211222011 |
4 | 131311222300333102020133 |
5 | 114200043401414010333 |
6 | 1143034512320332051 |
7 | 36433104301205215 |
oct | 3565526077221037 |
9 | 565577156554864 |
10 | 131231400141343 |
11 | 388a5a19203257 |
12 | 12875636474027 |
13 | 582c0b6332b88 |
14 | 24598c2a7ccb5 |
15 | 102896ac7e9cd |
hex | 775ab0fd221f |
131231400141343 has 2 divisors, whose sum is σ = 131231400141344. Its totient is φ = 131231400141342.
The previous prime is 131231400141299. The next prime is 131231400141407. The reversal of 131231400141343 is 343141004132131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131231400141343 - 213 = 131231400133151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131231400141943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65615700070671 + 65615700070672.
It is an arithmetic number, because the mean of its divisors is an integer number (65615700070672).
Almost surely, 2131231400141343 is an apocalyptic number.
131231400141343 is a deficient number, since it is larger than the sum of its proper divisors (1).
131231400141343 is an equidigital number, since it uses as much as digits as its factorization.
131231400141343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 131231400141343 its reverse (343141004132131), we get a palindrome (474372404273474).
The spelling of 131231400141343 in words is "one hundred thirty-one trillion, two hundred thirty-one billion, four hundred million, one hundred forty-one thousand, three hundred forty-three".
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