Base | Representation |
---|---|
bin | 11101110101101010110000… |
… | …111111010010001001011111 |
3 | 122012122121011220121212001112 |
4 | 131311222300333102021133 |
5 | 114200043401414011112 |
6 | 1143034512320332235 |
7 | 36433104301205336 |
oct | 3565526077221137 |
9 | 565577156555045 |
10 | 131231400141407 |
11 | 388a5a19203305 |
12 | 1287563647407b |
13 | 582c0b6332c07 |
14 | 24598c2a7cd1d |
15 | 102896ac7ea22 |
hex | 775ab0fd225f |
131231400141407 has 2 divisors, whose sum is σ = 131231400141408. Its totient is φ = 131231400141406.
The previous prime is 131231400141343. The next prime is 131231400141511. The reversal of 131231400141407 is 704141004132131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131231400141407 - 26 = 131231400141343 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131231400143407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65615700070703 + 65615700070704.
It is an arithmetic number, because the mean of its divisors is an integer number (65615700070704).
Almost surely, 2131231400141407 is an apocalyptic number.
131231400141407 is a deficient number, since it is larger than the sum of its proper divisors (1).
131231400141407 is an equidigital number, since it uses as much as digits as its factorization.
131231400141407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 32.
Adding to 131231400141407 its reverse (704141004132131), we get a palindrome (835372404273538).
The spelling of 131231400141407 in words is "one hundred thirty-one trillion, two hundred thirty-one billion, four hundred million, one hundred forty-one thousand, four hundred seven".
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