1312314433 has 2 divisors, whose sum is σ = 1312314434. Its totient is φ = 1312314432.

The previous prime is 1312314431. The next prime is 1312314457. The reversal of 1312314433 is 3344132131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1308124224 + 4190209 = 36168^2 + 2047^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312314433 - 2¹ = 1312314431 is a prime.

It is a super-2 number, since 2×1312314433² = 3444338342120222978, which contains 22 as substring.

Together with 1312314431, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1312314398 and 1312314407.

It is not a weakly prime, because it can be changed into another prime (1312314431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656157216 + 656157217.

It is an arithmetic number, because the mean of its divisors is an integer number (656157217).

Almost surely, 2^1312314433 is an apocalyptic number.

It is an amenable number.

1312314433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312314433 is an equidigital number, since it uses as much as digits as its factorization.

1312314433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2592, while the sum is 25.

The square root of 1312314433 is about 36225.8807070304. The cubic root of 1312314433 is about 1094.8281829064.

Adding to 1312314433 its reverse (3344132131), we get a palindrome (4656446564).

It can be divided in two parts, 13123 and 14433, that added together give a square (27556 = 166²).

The spelling of 1312314433 in words is "one billion, three hundred twelve million, three hundred fourteen thousand, four hundred thirty-three".