131232311323031 has 2 divisors, whose sum is σ = 131232311323032. Its totient is φ = 131232311323030.

The previous prime is 131232311323019. The next prime is 131232311323033. The reversal of 131232311323031 is 130323113232131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131232311323031 is a prime.

It is a super-2 number, since 2×131232311323031² (a number of 29 digits) contains 22 as substring.

Together with 131232311323033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 131232311322985 and 131232311323003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131232311323033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65616155661515 + 65616155661516.

It is an arithmetic number, because the mean of its divisors is an integer number (65616155661516).

Almost surely, 2^{131232311323031} is an apocalyptic number.

131232311323031 is a deficient number, since it is larger than the sum of its proper divisors (1).

131232311323031 is an equidigital number, since it uses as much as digits as its factorization.

131232311323031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5832, while the sum is 29.

Adding to 131232311323031 its reverse (130323113232131), we get a palindrome (261555424555162).

The spelling of 131232311323031 in words is "one hundred thirty-one trillion, two hundred thirty-two billion, three hundred eleven million, three hundred twenty-three thousand, thirty-one".