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13123305423047 is a prime number
BaseRepresentation
bin1011111011111000000111…
…1101010100000011000111
31201110120112201102000202202
42332332001331110003013
53210003012142014142
643524432511425115
72523061512403601
oct276760175240307
951416481360682
1013123305423047
1141aa6208730a6
12157b47452519b
137426a39032c1
1433525835a171
1517b579912032
hexbef81f540c7

13123305423047 has 2 divisors, whose sum is σ = 13123305423048. Its totient is φ = 13123305423046.

The previous prime is 13123305422933. The next prime is 13123305423133. The reversal of 13123305423047 is 74032450332131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13123305423047 - 220 = 13123304374471 is a prime.

It is a super-2 number, since 2×131233054230472 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13123305423047.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13123305423947) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561652711523 + 6561652711524.

It is an arithmetic number, because the mean of its divisors is an integer number (6561652711524).

Almost surely, 213123305423047 is an apocalyptic number.

13123305423047 is a deficient number, since it is larger than the sum of its proper divisors (1).

13123305423047 is an equidigital number, since it uses as much as digits as its factorization.

13123305423047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 181440, while the sum is 38.

Adding to 13123305423047 its reverse (74032450332131), we get a palindrome (87155755755178).

The spelling of 13123305423047 in words is "thirteen trillion, one hundred twenty-three billion, three hundred five million, four hundred twenty-three thousand, forty-seven".