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1312332433 is a prime number
BaseRepresentation
bin100111000111000…
…1001101010010001
310101110101101122221
41032032021222101
510141424114213
6334115501041
744343433036
oct11616115221
93343341587
101312332433
11613860865
123075b7781
1317bb65389
14c641138d
157a32938d
hex4e389a91

1312332433 has 2 divisors, whose sum is σ = 1312332434. Its totient is φ = 1312332432.

The previous prime is 1312332431. The next prime is 1312332479. The reversal of 1312332433 is 3342332131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 833072769 + 479259664 = 28863^2 + 21892^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312332433 - 21 = 1312332431 is a prime.

It is a super-4 number, since 4×13123324334 (a number of 38 digits) contains 4444 as substring.

Together with 1312332431, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1312332398 and 1312332407.

It is not a weakly prime, because it can be changed into another prime (1312332431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656166216 + 656166217.

It is an arithmetic number, because the mean of its divisors is an integer number (656166217).

Almost surely, 21312332433 is an apocalyptic number.

It is an amenable number.

1312332433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312332433 is an equidigital number, since it uses as much as digits as its factorization.

1312332433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3888, while the sum is 25.

The square root of 1312332433 is about 36226.1291473434. The cubic root of 1312332433 is about 1094.8331885201.

Adding to 1312332433 its reverse (3342332131), we get a palindrome (4654664564).

The spelling of 1312332433 in words is "one billion, three hundred twelve million, three hundred thirty-two thousand, four hundred thirty-three".