Base | Representation |
---|---|
bin | 11101110101101100100011… |
… | …011110110100011110011101 |
3 | 122012122210010210002010220112 |
4 | 131311230203132310132131 |
5 | 114200111320134323401 |
6 | 1143035431055255405 |
7 | 36433203014265461 |
oct | 3565544336643635 |
9 | 565583123063815 |
10 | 131233321011101 |
11 | 388a6814513121 |
12 | 12875a9181a565 |
13 | 582c3312929ba |
14 | 2459a25c1a4a1 |
15 | 1028a2e7113bb |
hex | 775b237b479d |
131233321011101 has 2 divisors, whose sum is σ = 131233321011102. Its totient is φ = 131233321011100.
The previous prime is 131233321011011. The next prime is 131233321011103. The reversal of 131233321011101 is 101110123332131.
Together with previous prime (131233321011011) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 95513991811876 + 35719329199225 = 9773126^2 + 5976565^2 .
It is an emirp because it is prime and its reverse (101110123332131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131233321011101 - 226 = 131233253902237 is a prime.
It is a Sophie Germain prime.
Together with 131233321011103, it forms a pair of twin primes.
It is a Chen prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131233321011103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65616660505550 + 65616660505551.
It is an arithmetic number, because the mean of its divisors is an integer number (65616660505551).
Almost surely, 2131233321011101 is an apocalyptic number.
It is an amenable number.
131233321011101 is a deficient number, since it is larger than the sum of its proper divisors (1).
131233321011101 is an equidigital number, since it uses as much as digits as its factorization.
131233321011101 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 131233321011101 its reverse (101110123332131), we get a palindrome (232343444343232).
The spelling of 131233321011101 in words is "one hundred thirty-one trillion, two hundred thirty-three billion, three hundred twenty-one million, eleven thousand, one hundred one".
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