Base | Representation |
---|---|
bin | 11101110101101110001110… |
… | …010010110001101111000111 |
3 | 122012122221202200001102212002 |
4 | 131311232032102301233013 |
5 | 114200124002413010023 |
6 | 1143040324552215515 |
7 | 36433265304134354 |
oct | 3565561622615707 |
9 | 565587680042762 |
10 | 131235113016263 |
11 | 388a7554007123 |
12 | 128762b199a59b |
13 | 582c558613a99 |
14 | 2459b55c1162b |
15 | 1028ad6bdab28 |
hex | 775b8e4b1bc7 |
131235113016263 has 2 divisors, whose sum is σ = 131235113016264. Its totient is φ = 131235113016262.
The previous prime is 131235113016251. The next prime is 131235113016323. The reversal of 131235113016263 is 362610311532131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131235113016263 - 222 = 131235108821959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131235113016223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65617556508131 + 65617556508132.
It is an arithmetic number, because the mean of its divisors is an integer number (65617556508132).
Almost surely, 2131235113016263 is an apocalyptic number.
131235113016263 is a deficient number, since it is larger than the sum of its proper divisors (1).
131235113016263 is an equidigital number, since it uses as much as digits as its factorization.
131235113016263 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 58320, while the sum is 38.
Adding to 131235113016263 its reverse (362610311532131), we get a palindrome (493845424548394).
The spelling of 131235113016263 in words is "one hundred thirty-one trillion, two hundred thirty-five billion, one hundred thirteen million, sixteen thousand, two hundred sixty-three".
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