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13123602564439 is a prime number
BaseRepresentation
bin1011111011111001001110…
…1010110100010101010111
31201110121022102112101010111
42332332103222310111113
53210004114224030224
643524522204303451
72523102051146203
oct276762352642527
951417272471114
1013123602564439
1141aa7635748a4
12157b537b41b87
1374272033cc03
143352859c7b03
1517b595a58d94
hexbef93ab4557

13123602564439 has 2 divisors, whose sum is σ = 13123602564440. Its totient is φ = 13123602564438.

The previous prime is 13123602564377. The next prime is 13123602564491. The reversal of 13123602564439 is 93446520632131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13123602564439 - 217 = 13123602433367 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13123602564392 and 13123602564401.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13123602564139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561801282219 + 6561801282220.

It is an arithmetic number, because the mean of its divisors is an integer number (6561801282220).

Almost surely, 213123602564439 is an apocalyptic number.

13123602564439 is a deficient number, since it is larger than the sum of its proper divisors (1).

13123602564439 is an equidigital number, since it uses as much as digits as its factorization.

13123602564439 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2799360, while the sum is 49.

The spelling of 13123602564439 in words is "thirteen trillion, one hundred twenty-three billion, six hundred two million, five hundred sixty-four thousand, four hundred thirty-nine".