Base | Representation |
---|---|
bin | 1011111011111001001110… |
… | …1010110100010101010111 |
3 | 1201110121022102112101010111 |
4 | 2332332103222310111113 |
5 | 3210004114224030224 |
6 | 43524522204303451 |
7 | 2523102051146203 |
oct | 276762352642527 |
9 | 51417272471114 |
10 | 13123602564439 |
11 | 41aa7635748a4 |
12 | 157b537b41b87 |
13 | 74272033cc03 |
14 | 3352859c7b03 |
15 | 17b595a58d94 |
hex | bef93ab4557 |
13123602564439 has 2 divisors, whose sum is σ = 13123602564440. Its totient is φ = 13123602564438.
The previous prime is 13123602564377. The next prime is 13123602564491. The reversal of 13123602564439 is 93446520632131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13123602564439 - 217 = 13123602433367 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13123602564392 and 13123602564401.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13123602564139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561801282219 + 6561801282220.
It is an arithmetic number, because the mean of its divisors is an integer number (6561801282220).
Almost surely, 213123602564439 is an apocalyptic number.
13123602564439 is a deficient number, since it is larger than the sum of its proper divisors (1).
13123602564439 is an equidigital number, since it uses as much as digits as its factorization.
13123602564439 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2799360, while the sum is 49.
The spelling of 13123602564439 in words is "thirteen trillion, one hundred twenty-three billion, six hundred two million, five hundred sixty-four thousand, four hundred thirty-nine".
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