Base | Representation |
---|---|
bin | 1011111011111001001110… |
… | …1010110100010110001011 |
3 | 1201110121022102112101012102 |
4 | 2332332103222310112023 |
5 | 3210004114224030431 |
6 | 43524522204304015 |
7 | 2523102051146306 |
oct | 276762352642613 |
9 | 51417272471172 |
10 | 13123602564491 |
11 | 41aa763574941 |
12 | 157b537b4200b |
13 | 74272033cc43 |
14 | 3352859c7b3d |
15 | 17b595a58dcb |
hex | bef93ab458b |
13123602564491 has 2 divisors, whose sum is σ = 13123602564492. Its totient is φ = 13123602564490.
The previous prime is 13123602564439. The next prime is 13123602564509. The reversal of 13123602564491 is 19446520632131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13123602564491 - 238 = 12848724657547 is a prime.
It is not a weakly prime, because it can be changed into another prime (13123602560491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561801282245 + 6561801282246.
It is an arithmetic number, because the mean of its divisors is an integer number (6561801282246).
Almost surely, 213123602564491 is an apocalyptic number.
13123602564491 is a deficient number, since it is larger than the sum of its proper divisors (1).
13123602564491 is an equidigital number, since it uses as much as digits as its factorization.
13123602564491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 933120, while the sum is 47.
The spelling of 13123602564491 in words is "thirteen trillion, one hundred twenty-three billion, six hundred two million, five hundred sixty-four thousand, four hundred ninety-one".
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