Base | Representation |
---|---|
bin | 10011000110001111010… |
… | …101101111100011101101 |
3 | 11122110110022102210200222 |
4 | 103012033111233203231 |
5 | 133000213141220424 |
6 | 2442521104501125 |
7 | 163546514545466 |
oct | 23061725574355 |
9 | 4573408383628 |
10 | 1312369866989 |
11 | 466633638365 |
12 | 19241a01a7a5 |
13 | 969a9a7cb6c |
14 | 4773a365d6d |
15 | 2420eda5e5e |
hex | 1318f56f8ed |
1312369866989 has 2 divisors, whose sum is σ = 1312369866990. Its totient is φ = 1312369866988.
The previous prime is 1312369866979. The next prime is 1312369866991. The reversal of 1312369866989 is 9896689632131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 866034972100 + 446334894889 = 930610^2 + 668083^2 .
It is a cyclic number.
It is not a de Polignac number, because 1312369866989 - 28 = 1312369866733 is a prime.
It is a super-2 number, since 2×13123698669892 (a number of 25 digits) contains 22 as substring.
Together with 1312369866991, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312369866949) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656184933494 + 656184933495.
It is an arithmetic number, because the mean of its divisors is an integer number (656184933495).
Almost surely, 21312369866989 is an apocalyptic number.
It is an amenable number.
1312369866989 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312369866989 is an equidigital number, since it uses as much as digits as its factorization.
1312369866989 is an evil number, because the sum of its binary digits is even.
The product of its digits is 181398528, while the sum is 71.
The spelling of 1312369866989 in words is "one trillion, three hundred twelve billion, three hundred sixty-nine million, eight hundred sixty-six thousand, nine hundred eighty-nine".
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