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13124101141 is a prime number
BaseRepresentation
bin11000011100100000…
…11110010000010101
31020212122022102020001
430032100132100111
5203334232214031
610010143011301
7643141006354
oct141620362025
936778272201
1013124101141
115625238488
122663299b31
131312003528
148c703199b
1551c2b7861
hex30e41e415

13124101141 has 2 divisors, whose sum is σ = 13124101142. Its totient is φ = 13124101140.

The previous prime is 13124101121. The next prime is 13124101153. The reversal of 13124101141 is 14110142131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11679341041 + 1444760100 = 108071^2 + 38010^2 .

It is an emirp because it is prime and its reverse (14110142131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13124101141 - 221 = 13122003989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13124101121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562050570 + 6562050571.

It is an arithmetic number, because the mean of its divisors is an integer number (6562050571).

Almost surely, 213124101141 is an apocalyptic number.

It is an amenable number.

13124101141 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124101141 is an equidigital number, since it uses as much as digits as its factorization.

13124101141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 13124101141 its reverse (14110142131), we get a palindrome (27234243272).

The spelling of 13124101141 in words is "thirteen billion, one hundred twenty-four million, one hundred one thousand, one hundred forty-one".