13124110001020 has 24 divisors (see below), whose sum is σ = 27561633380064. Its totient is φ = 5249453071296.

The previous prime is 13124110001017. The next prime is 13124110001021. The reversal of 13124110001020 is 2010001142131.

It is a junction number, because it is equal to n+sod(n) for n = 13124110000985 and 13124110001003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13124110001021) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11368767 + ... + 12469846.

It is an arithmetic number, because the mean of its divisors is an integer number (1148401390836).

Almost surely, 2^{13124110001020} is an apocalyptic number.

13124110001020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13124110001020 is an abundant number, since it is smaller than the sum of its proper divisors (14437523379044).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13124110001020 is a wasteful number, since it uses less digits than its factorization.

13124110001020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23866149 (or 23866147 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 13124110001020 its reverse (2010001142131), we get a palindrome (15134111143151).

The spelling of 13124110001020 in words is "thirteen trillion, one hundred twenty-four billion, one hundred ten million, one thousand, twenty".