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131241423301 is a prime number
BaseRepresentation
bin111101000111010011…
…0010011000111000101
3110112202102220002020121
41322032212103013011
54122240301021201
6140142543101541
712324166456162
oct1721646230705
9415672802217
10131241423301
11507283a88aa
12215285a18b1
13c4b7140631
1464d02dd069
153631d329a1
hex1e8e9931c5

131241423301 has 2 divisors, whose sum is σ = 131241423302. Its totient is φ = 131241423300.

The previous prime is 131241423293. The next prime is 131241423319. The reversal of 131241423301 is 103324142131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 115023400801 + 16218022500 = 339151^2 + 127350^2 .

It is a cyclic number.

It is not a de Polignac number, because 131241423301 - 23 = 131241423293 is a prime.

It is a super-2 number, since 2×1312414233012 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131241423371) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65620711650 + 65620711651.

It is an arithmetic number, because the mean of its divisors is an integer number (65620711651).

Almost surely, 2131241423301 is an apocalyptic number.

It is an amenable number.

131241423301 is a deficient number, since it is larger than the sum of its proper divisors (1).

131241423301 is an equidigital number, since it uses as much as digits as its factorization.

131241423301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 131241423301 its reverse (103324142131), we get a palindrome (234565565432).

The spelling of 131241423301 in words is "one hundred thirty-one billion, two hundred forty-one million, four hundred twenty-three thousand, three hundred one".