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131242031140440 = 233511439643239783
BaseRepresentation
bin11101110101110100101010…
…101001010100111001011000
3122012200121121210201120010110
4131311310222221110321120
5114200232134432443230
61143043431243444320
736433631610205533
oct3565645251247130
9565617553646113
10131242031140440
11388aa484119220
12128777028266a0
1358300bb98089c
14245a210937a1a
151028d8e2304b0
hex775d2aa54e58

131242031140440 has 256 divisors, whose sum is σ = 439555608391680. Its totient is φ = 31072984911360.

The previous prime is 131242031140421. The next prime is 131242031140453. The reversal of 131242031140440 is 44041130242131.

It is a happy number.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 131242031140398 and 131242031140407.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 547216789 + ... + 547456571.

It is an arithmetic number, because the mean of its divisors is an integer number (1717014095280).

Almost surely, 2131242031140440 is an apocalyptic number.

131242031140440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131242031140440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (219777804195840).

131242031140440 is an abundant number, since it is smaller than the sum of its proper divisors (308313577251240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131242031140440 is a wasteful number, since it uses less digits than its factorization.

131242031140440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 249494 (or 249490 counting only the distinct ones).

The product of its (nonzero) digits is 9216, while the sum is 30.

Adding to 131242031140440 its reverse (44041130242131), we get a palindrome (175283161382571).

The spelling of 131242031140440 in words is "one hundred thirty-one trillion, two hundred forty-two billion, thirty-one million, one hundred forty thousand, four hundred forty".