Base | Representation |
---|---|
bin | 1011111011111011100000… |
… | …1000111100100010011110 |
3 | 1201110122220001212222112122 |
4 | 2332332320020330202132 |
5 | 3210011342344122032 |
6 | 43525103023102542 |
7 | 2523123161055206 |
oct | 276767010744236 |
9 | 51418801788478 |
10 | 13124214442142 |
11 | 41aaa479a5651 |
12 | 157b688a41a52 |
13 | 7427ba036c1b |
14 | 335302d83406 |
15 | 17b5ce621012 |
hex | befb823c89e |
13124214442142 has 4 divisors (see below), whose sum is σ = 19686321663216. Its totient is φ = 6562107221070.
The previous prime is 13124214442123. The next prime is 13124214442147. The reversal of 13124214442142 is 24124441242131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13124214442147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3281053610534 + ... + 3281053610537.
It is an arithmetic number, because the mean of its divisors is an integer number (4921580415804).
Almost surely, 213124214442142 is an apocalyptic number.
13124214442142 is a deficient number, since it is larger than the sum of its proper divisors (6562107221074).
13124214442142 is an equidigital number, since it uses as much as digits as its factorization.
13124214442142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6562107221073.
The product of its digits is 49152, while the sum is 35.
Adding to 13124214442142 its reverse (24124441242131), we get a palindrome (37248655684273).
The spelling of 13124214442142 in words is "thirteen trillion, one hundred twenty-four billion, two hundred fourteen million, four hundred forty-two thousand, one hundred forty-two".
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