Base | Representation |
---|---|
bin | 111101000111010101… |
… | …0000010100011001000 |
3 | 110112202111201220120021 |
4 | 1322032222002203020 |
5 | 4122241023412130 |
6 | 140143020110224 |
7 | 12324211012366 |
oct | 1721652024310 |
9 | 415674656507 |
10 | 131242404040 |
11 | 50728a08730 |
12 | 21528995374 |
13 | c4b73c4b57 |
14 | 64d04b6636 |
15 | 3631e7837a |
hex | 1e8ea828c8 |
131242404040 has 64 divisors (see below), whose sum is σ = 336146578560. Its totient is φ = 45649528320.
The previous prime is 131242404019. The next prime is 131242404061. The reversal of 131242404040 is 40404242131.
It is an interprime number because it is at equal distance from previous prime (131242404019) and next prime (131242404061).
It is a junction number, because it is equal to n+sod(n) for n = 131242403996 and 131242404014.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6474189 + ... + 6494428.
It is an arithmetic number, because the mean of its divisors is an integer number (5252290290).
Almost surely, 2131242404040 is an apocalyptic number.
131242404040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131242404040 is an abundant number, since it is smaller than the sum of its proper divisors (204904174520).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131242404040 is a wasteful number, since it uses less digits than its factorization.
131242404040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12968662 (or 12968658 counting only the distinct ones).
The product of its (nonzero) digits is 3072, while the sum is 25.
Adding to 131242404040 its reverse (40404242131), we get a palindrome (171646646171).
The spelling of 131242404040 in words is "one hundred thirty-one billion, two hundred forty-two million, four hundred four thousand, forty".
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