13124330413 has 2 divisors, whose sum is σ = 13124330414. Its totient is φ = 13124330412.

The previous prime is 13124330381. The next prime is 13124330437. The reversal of 13124330413 is 31403342131.

13124330413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11221800489 + 1902529924 = 105933^2 + 43618^2 .

It is a cyclic number.

It is not a de Polignac number, because 13124330413 - 2⁵ = 13124330381 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13124330473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562165206 + 6562165207.

It is an arithmetic number, because the mean of its divisors is an integer number (6562165207).

Almost surely, 2^13124330413 is an apocalyptic number.

It is an amenable number.

13124330413 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124330413 is an equidigital number, since it uses as much as digits as its factorization.

13124330413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13124330413 its reverse (31403342131), we get a palindrome (44527672544).

The spelling of 13124330413 in words is "thirteen billion, one hundred twenty-four million, three hundred thirty thousand, four hundred thirteen".