Base | Representation |
---|---|
bin | 1011111011111011111101… |
… | …0110011000010000101101 |
3 | 1201110200012111111111010022 |
4 | 2332332333112120100231 |
5 | 3210012114330412302 |
6 | 43525123023451525 |
7 | 2523126160164002 |
oct | 276767726302055 |
9 | 51420174444108 |
10 | 13124335404077 |
11 | 41aaaaa204097 |
12 | 157b701456ba5 |
13 | 742809109931 |
14 | 33531506d8a9 |
15 | 17b5da0668a2 |
hex | befbf59842d |
13124335404077 has 2 divisors, whose sum is σ = 13124335404078. Its totient is φ = 13124335404076.
The previous prime is 13124335404053. The next prime is 13124335404133. The reversal of 13124335404077 is 77040453342131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9385271204521 + 3739064199556 = 3063539^2 + 1933666^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13124335404077 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13124335404277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562167702038 + 6562167702039.
It is an arithmetic number, because the mean of its divisors is an integer number (6562167702039).
Almost surely, 213124335404077 is an apocalyptic number.
It is an amenable number.
13124335404077 is a deficient number, since it is larger than the sum of its proper divisors (1).
13124335404077 is an equidigital number, since it uses as much as digits as its factorization.
13124335404077 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 846720, while the sum is 44.
The spelling of 13124335404077 in words is "thirteen trillion, one hundred twenty-four billion, three hundred thirty-five million, four hundred four thousand, seventy-seven".
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